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a(n) = 2^A031142(n).
1

%I #11 Apr 12 2020 06:14:38

%S 1,16,128,8192,16384,262144,16777216,134217728,2147483648,17179869184,

%T 137438953472,562949953421312,2251799813685248,147573952589676412928,

%U 4722366482869645213696,75557863725914323419136,151115727451828646838272,2417851639229258349412352,77371252455336267181195264,680564733841876926926749214863536422912

%N a(n) = 2^A031142(n).

%C Powers of 2 such that there is an increasing number of nonzero digits after the rightmost digit 0, including a leading 0. a(20)=2^129 is the first term where the rightmost 0 is not the leading 0. - _Hugo Pfoertner_, Apr 12 2020

%Y Cf. A031142, A031155.

%K nonn,base

%O 1,2

%A _N. J. A. Sloane_.