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a(n+1) = Sum_{k=0..floor(4*n/5)} a(k) * a(n-k).
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%I #11 Oct 15 2021 21:30:07

%S 1,1,1,2,4,9,21,42,97,233,570,1414,3319,8208,20595,52370,133955,

%T 328261,833652,2136155,5519116,14341917,36069212,93074465,241613666,

%U 630653714,1652472131,4215072482,10985970447,28756470626,75580683613,199201407564,513021407584

%N a(n+1) = Sum_{k=0..floor(4*n/5)} a(k) * a(n-k).

%H Seiichi Manyama, <a href="/A030039/b030039.txt">Table of n, a(n) for n = 0..1000</a>

%o (PARI) lista(nn) = {my(v=vector(nn+2, i, 1)); for(n=1, nn, v[n+2]=sum(k=1, 1+(4*n)\5, v[k]*v[n+2-k])); v; } \\ _Jinyuan Wang_, Mar 18 2020

%Y Cf. A000992, A030036, A030037, A030038.

%K nonn

%O 0,4

%A _N. J. A. Sloane_

%E More terms from _Jinyuan Wang_, Mar 18 2020