A029923 - OEIS

%I #30 May 08 2018 15:11:55

%S 0,0,1,1,2,2,3,3,4,4,5,5,5,6,6,7,7,8,8,9,9,10,10,10,11,11,12,12,13,13,

%T 14,14,15,15,15,16,16,17,17,18,18,19,19,20,20,20,21,21,22,22,23,23,24,

%U 24,24,25,25,26,26,27,27

%N Convert n from pounds (lbs) to kilograms (kg).

%C This sequence is a(n) = floor(n*0.45359237 + 1/2). The current (1959) definition of the international pound is 1 pound = 0.45359237 kilograms. - _Charles R Greathouse IV_, Mar 07 2016

%D M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards Applied Math. Series 55, Tenth Printing, 1972, p. 8.

%H Lee A. Newberg, <a href="/A029923/b029923.txt">Table of n, a(n) for n = 0..1000</a>

%H M. Abramowitz and I. A. Stegun, eds., <a href="http://www.convertit.com/Go/ConvertIt/Reference/AMS55.ASP">Handbook of Mathematical Functions</a>, National Bureau of Standards, Applied Math. Series 55, Tenth Printing, 1972 [alternative scanned copy].

%H M. Abramowitz and I. A. Stegun, eds., <a href="http://www.convertit.com/Go/ConvertIt/Reference/AMS55.ASP">Handbook of Mathematical Functions</a>, National Bureau of Standards Applied Math. Series 55, Tenth Printing, 1972, p. 8.

%p [seq(floor(n*0.45359237+(1/2)),n=0..60)]; # _Muniru A Asiru_, Apr 10 2018

%t Array[Floor[#*.45359237 + 1/2] &, 61, 0] (* _Michael De Vlieger_, Apr 10 2018 *)

%Y Cf. A029924.

%K nonn,easy

%O 0,5

%A _N. J. A. Sloane_.

%E Offset, comments, formula, and program text that was applicable to the original sequence, which was floor(n/2.2), updated or deleted by _Lee A. Newberg_, Apr 10 2018