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Expansion of 1/((1-5x)(1-9x)(1-11x)(1-12x)).
0

%I #15 Aug 31 2018 19:27:16

%S 1,37,870,16610,281171,4403367,65339080,932218420,12912631941,

%T 174806957897,2323925673290,30446318392230,394142295428311,

%U 5052076439311627,64222440261259500,810705252920074040

%N Expansion of 1/((1-5x)(1-9x)(1-11x)(1-12x)).

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (37,-499,2883,-5940)

%F a(n) = 23*a(n-1) - 132*a(n-2) + (9^(n+1) - 5^(n+1))/4, n >= 2. - _Vincenzo Librandi_, Mar 12 2011

%F a(n) = 4*12^(n+2)/7 - 5^(n+3)/168 - 11^(n+3)/12 + 3*9^(n+2)/8. - _R. J. Mathar_, Mar 18 2011

%t CoefficientList[Series[1/((1-5x)(1-9x)(1-11x)(1-12x)),{x,0,20}],x] (* or *) LinearRecurrence[{37,-499,2883,-5940},{1,37,870,16610},20] (* _Harvey P. Dale_, Feb 06 2017 *)

%K nonn

%O 0,2

%A _N. J. A. Sloane_