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%I #13 Oct 27 2019 11:36:24
%S 1,3,5,13,24,58,111,257,500,1126,2210,4882,9632,20980,41531,89497,
%T 177564,379438,754014,1600406,3184016,6720748,13382710,28117498,
%U 56026984,117254268,233765636,487589572,972504704,2022568168
%N a(n) = Sum_{k=0..floor((n+1)/2)} (k+1) * A008315(n, k).
%F a(2n) = A065982(n+1)/2 = (n+2)*binomial(2n+2, n+1)/2 - 4^n.
%Y Cf. A065982.
%K nonn
%O 0,2
%A _Clark Kimberling_