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Exponent of 3 (value of i) in n-th number of form 3^i*4^j.
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%I #12 Jan 28 2021 21:36:49

%S 0,1,0,2,1,0,3,2,1,0,4,3,2,1,5,0,4,3,2,6,1,5,0,4,3,7,2,6,1,5,0,4,8,3,

%T 7,2,6,1,5,0,9,4,8,3,7,2,6,1,10,5,0,9,4,8,3,7,2,11,6,1,10,5,0,9,4,8,3,

%U 12,7,2,11,6,1,10,5,0,9,4,13,8,3,12,7,2,11,6,1,10,5,0,14,9,4,13,8,3,12,7,2,11,6

%N Exponent of 3 (value of i) in n-th number of form 3^i*4^j.

%H David A. Corneth, <a href="/A025640/b025640.txt">Table of n, a(n) for n = 1..10000</a>

%e a(20) = 6 as the 20th number of the form 3^i * 4^j is 729 = 3^6 * 4^0 (See A025613). So the value of i in that factorization is the exponent of 3 which is 6. - _David A. Corneth_, Jan 28 2021

%Y Cf. A025613.

%K nonn

%O 1,4

%A _David W. Wilson_