A025146 (#1's in s(1),...,s(n)) - (#1's in r(1),...,r(n)), where s = A025142 and r = A025143.

1, 1, 1, 2, 2, 2, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 0, -1, 0, 1, 0, 1, 1, 0, 0, 0, -1, 0, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 1, 2, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 1, 1, 1, 2, 1, 1, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 1, 0, 1, 2, 1, 1, 2, 1, 0, 1, 1, 1, 2, 1, 1, 1, 0, 0, 0, 0, 0, 1, 1, 1, 2, 1, 0, 1, 0

Offset

1,4

Links

Table of n, a(n) for n=1..110.

H. Harborth, Probleme und Lösungen, Mathematische Semesterberichte 44 (1997) 94.

Crossrefs

Sequence in context: A237413 A157343 A102679 * A067397 A080586 A152906

Adjacent sequences: A025143 A025144 A025145 * A025147 A025148 A025149

Keyword

sign

Author

Clark Kimberling

Status

approved