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a(n) = floor(n/{n*Pi}), where { } = fractional part.
1

%I #11 Apr 11 2021 21:49:37

%S 7,7,7,7,7,7,7,60,32,24,19,17,15,14,121,60,41,32,27,24,21,191,89,60,

%T 46,38,32,29,273,121,79,60,49,41,36,369,154,99,74,60,50,44,485,191,

%U 121,89,71,60,52,627,230,143,105,83,69,60,805,273,166,121,95,79,68,1033,319,191,137,108

%N a(n) = floor(n/{n*Pi}), where { } = fractional part.

%H Clark Kimberling, <a href="/A024583/b024583.txt">Table of n, a(n) for n = 1..1000</a>

%t Table[Floor[n/FractionalPart[n*Pi]], {n, 70}] (* _Clark Kimberling_, Aug 18 2012 *)

%Y Cf. A024584.

%K nonn

%O 1,1

%A _Clark Kimberling_