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a(n) = Sum_{k=1..n} [ 1/{k*e} ] where {x} := x - [ x ].
2

%I #13 Jul 17 2019 06:59:23

%S 1,3,9,10,11,14,49,50,52,57,58,59,61,78,79,81,85,86,87,89,100,101,102,

%T 106,107,108,110,118,119,120,123,124,125,127,134,135,136,139,215,216,

%U 218,223,224,225,228,252,253,255,260,261,262,264,278,279,280,284,285,286,288,298

%N a(n) = Sum_{k=1..n} [ 1/{k*e} ] where {x} := x - [ x ].

%H Clark Kimberling, <a href="/A024574/b024574.txt">Table of n, a(n) for n = 1..1000</a>

%t Table[Sum[Floor[1/FractionalPart[k*E]], {k, n}], {n, 100}] (* _Clark Kimberling_, Aug 15 2012 *)

%Y Cf. A024575. Partial sums of A024573.

%K nonn

%O 1,2

%A _Clark Kimberling_