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a(n) = [ 1/{n/sqrt(2)} ], where {x} := x - [ x ].
3

%I #9 Aug 03 2014 14:27:15

%S 1,2,8,1,1,4,1,1,2,14,1,2,5,1,1,3,48,1,2,7,1,1,3,1,1,2,10,1,1,4,1,1,2,

%T 24,1,2,6,1,1,3,1,1,2,8,1,1,4,1,1,2,16,1,2,5,1,1,3,82,1,2,7,1,1,3,1,1,

%U 2,12,1,2,4,1,1,3,30,1,2,6,1,1,3,1,1,2,9,1,1,4,1,1,2,18,1,2,5,1,1,3,280,1

%N a(n) = [ 1/{n/sqrt(2)} ], where {x} := x - [ x ].

%H Clark Kimberling, <a href="/A024544/b024544.txt">Table of n, a(n) for n = 1..1000</a>

%t Table[Floor[1/FractionalPart[n/Sqrt[2]]], {n, 1, 100}] (* _Clark Kimberling_, Aug 17 2012 *)

%Y Cf. A024543.

%K nonn

%O 1,2

%A _Clark Kimberling_