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a(n) = [ C(2n,n)/n ].
1

%I #5 Nov 28 2014 14:12:01

%S 2,3,6,17,50,154,490,1608,5402,18475,64130,225346,800046,2865471,

%T 10341168,37567524,137270954,504174183,1860277042,6892326441,

%U 25631327354,95640861987,357975249026,1343650153462,5056424257510,19073789728773,72108867616596

%N a(n) = [ C(2n,n)/n ].

%t Table[Floor[Binomial[2n,n]/n],{n,40}] (* _Harvey P. Dale_, Nov 28 2014 *)

%K nonn

%O 1,1

%A _Clark Kimberling_