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A024212
2nd elementary symmetric function of first n+1 positive integers congruent to 1 mod 3.
10
4, 39, 159, 445, 1005, 1974, 3514, 5814, 9090, 13585, 19569, 27339, 37219, 49560, 64740, 83164, 105264, 131499, 162355, 198345, 240009, 287914, 342654, 404850, 475150, 554229, 642789, 741559, 851295, 972780, 1106824, 1254264, 1415964, 1592815, 1785735
OFFSET
1,1
FORMULA
a(n) = n*(n+1)*(9*n^2+9*n-2)/8.
From Clark Kimberling, Aug 18 2012: (Start)
a(n) = 5*a(n-1)-10*a(n-2)+10*a(n-3)-5*a(n-4)+a(n-5).
G.f.: (4 + 19*x + 4*x^2)/(1 - x)^5. (End)
From Wolfdieter Lang, Jul 30 2017: (Start)
E.g.f.: exp(x)*x*(32+124*x+72*x^2+9*x^3)/8 = exp(x)*x*(2 + x)*(16 + 54*x + 9*x^2)/8.
a(n) = A286718(n+1, n-1), n >= 1. (End)
Sum_{n>=1} 1/a(n) = 14 + 12*Pi*tan(sqrt(17)*Pi/6)/sqrt(17). - Amiram Eldar, Jul 10 2026
MATHEMATICA
Table[n(n+1)(9n^2+9n-2)/8, {n, 40}] (* Harvey P. Dale, Oct 16 2023 *)
(* Alternative: *)
LinearRecurrence[{5, -10, 10, -5, 1}, {4, 39, 159, 445, 1005}, 40] (* Harvey P. Dale, Oct 16 2023 *)
PROG
(Magma) [n*(n+1)*(9*n^2+9*n-2)/8: n in [1..40]]; // Vincenzo Librandi, Oct 10 2011
CROSSREFS
Sequence in context: A297736 A286359 A201740 * A006408 A112460 A296594
KEYWORD
nonn,easy,changed
STATUS
approved