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a(n) = 12^n - n^9.
2

%I #10 Sep 08 2022 08:44:48

%S 1,11,-368,-17955,-241408,-1704293,-7091712,-4521799,295763968,

%T 4772359863,60917364224,740650422997,8910940667904,106982600879699,

%U 1283897803502080,15406983131226993,184884190175559680

%N a(n) = 12^n - n^9.

%H Vincenzo Librandi, <a href="/A024149/b024149.txt">Table of n, a(n) for n = 0..300</a>

%o (Magma) [12^n-n^9: n in [0..20]]; // _Vincenzo Librandi_, Jul 02 2011

%K sign,easy

%O 0,2

%A _N. J. A. Sloane_