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a(n) = 12^n - n^8.
2

%I #10 Sep 08 2022 08:44:48

%S 1,11,-112,-4833,-44800,-141793,1306368,30067007,413204480,5116733631,

%T 61817364224,742794011807,8915670466560,106992389648351,

%U 1283916988759808,15407019011695743,184884254600069120

%N a(n) = 12^n - n^8.

%H Vincenzo Librandi, <a href="/A024148/b024148.txt">Table of n, a(n) for n = 0..300</a>

%o (Magma) [12^n-n^8: n in [0..20]]; // _Vincenzo Librandi_, Jul 02 2011

%K sign,easy

%O 0,2

%A _N. J. A. Sloane_