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a(n) = 10^n - n^8.
2

%I #19 Oct 20 2022 23:31:09

%S 1,9,-156,-5561,-55536,-290625,-679616,4235199,83222784,956953279,

%T 9900000000,99785641119,999570018304,9999184269279,99998524210944,

%U 999997437109375,9999995705032704,99999993024242559,999999988980039424

%N a(n) = 10^n - n^8.

%H Vincenzo Librandi, <a href="/A024122/b024122.txt">Table of n, a(n) for n = 0..300</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (19,-126,444,-966,1386,-1344,876,-369,91,-10).

%F a(n) = 19*a(n-1) - 126*a(n-2) + 444*a(n-3) - 966*a(n-4) + 1386*a(n-5) - 1344*a(n-6) + 876*a(n-7) - 369*a(n-8) + 91*a(n-9) - 10*a(n-10). - _Wesley Ivan Hurt_, Oct 20 2022

%o (Magma) [10^n-n^8: n in [0..20]]; // _Vincenzo Librandi_, Jul 01 2011

%o (PARI) a(n)=10^n-n^8 \\ _Charles R Greathouse IV_, Jul 01 2011

%K sign,easy

%O 0,2

%A _N. J. A. Sloane_