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a(n) = 4^n-n^9.
2

%I #10 Sep 08 2022 08:44:48

%S 1,3,-496,-19619,-261888,-1952101,-10073600,-40337223,-134152192,

%T -387158345,-998951424,-2353753387,-5143003136,-10537390509,

%U -20392611328,-37369617551,-64424509440,-101408007313,-129639813632

%N a(n) = 4^n-n^9.

%H Vincenzo Librandi, <a href="/A024045/b024045.txt">Table of n, a(n) for n = 0..500</a>

%o (Magma) [4^n-n^9: n in [0..30]]; // _Vincenzo Librandi_, Jul 02 2011

%K sign,easy

%O 0,2

%A _N. J. A. Sloane_.