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a(n) = 4^n - n^6.
3

%I #18 Sep 08 2022 08:44:48

%S 1,3,-48,-665,-3840,-14601,-42560,-101265,-196608,-269297,48576,

%T 2422743,13791232,62282055,260905920,1062351199,4278190080,

%U 17155731615,68685464512,274830861063,1099447627776

%N a(n) = 4^n - n^6.

%H Vincenzo Librandi, <a href="/A024042/b024042.txt">Table of n, a(n) for n = 0..500</a>

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (11, -49, 119, -175, 161, -91, 29, -4).

%F a(n) = 11*a(n-1) - 49*a(n-2) + 119*a(n-3) - 175*a(n-4) + 161*a(n-5) - 91*a(n-6) + 29*a(n-7) - 4*a(n-8); a(0)=1, a(1)=3, a(2)=-48, a(3)=-665, a(4)=-3840, a(5)=-14601, a(6)=-42560, a(7)=-101265. - _Harvey P. Dale_, Jun 25 2013

%t Table[4^n-n^6,{n,0,30}] (* or *) LinearRecurrence[ {11,-49,119,-175,161,-91,29,-4},{1,3,-48,-665,-3840,-14601,-42560,-101265},30] (* _Harvey P. Dale_, Jun 25 2013 *)

%o (Magma) [4^n-n^6: n in [0..30]]; // _Vincenzo Librandi_, Jul 02 2011

%K sign,easy

%O 0,2

%A _N. J. A. Sloane_