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a(n) = 1 - n^12.
3

%I #15 Sep 08 2022 08:44:48

%S 1,0,-4095,-531440,-16777215,-244140624,-2176782335,-13841287200,

%T -68719476735,-282429536480,-999999999999,-3138428376720,

%U -8916100448255,-23298085122480,-56693912375295,-129746337890624,-281474976710655

%N a(n) = 1 - n^12.

%H Vincenzo Librandi, <a href="/A024010/b024010.txt">Table of n, a(n) for n = 0..320</a>

%t 1-Range[0,20]^12 (* _Harvey P. Dale_, Feb 19 2012 *)

%o (Magma) [1-n^12: n in [0..35]]; // _Vincenzo Librandi_, Apr 29 2011

%Y a(n) = -A123868(n) for n>0.

%K sign,easy

%O 0,3

%A _N. J. A. Sloane_.