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A023408
If any power of 2 ends with k 5's and 6's, they must be the first k terms of this sequence in reverse order.
3
6, 5, 6, 6, 6, 5, 6, 6, 6, 6, 5, 6, 6, 6, 5, 6, 5, 5, 6, 5, 5, 5, 5, 6, 5, 5, 6, 6, 5, 6, 6, 6, 5, 6, 6, 6, 6, 6, 6, 5, 6, 6, 5, 6, 5, 6, 6, 5, 5, 5, 6, 5, 6, 5, 6, 6, 5, 5, 6, 5, 6, 5, 6, 6, 6, 5, 6, 6, 6, 5, 6, 6, 5, 5, 5, 6, 5, 5, 5, 5, 5, 6, 6, 6, 6, 5, 6, 5, 6, 5, 5, 6, 6, 5, 5, 6, 6, 5, 6, 6, 5, 6, 5, 6, 6, 6, 5, 5
OFFSET
1,1
LINKS
FORMULA
Conjecture: a(n) + A023402(n) = 9, for n > 1. - J. Lowell, Nov 16 2020
CROSSREFS
Cf. A023402.
Sequence in context: A242723 A111718 A106154 * A133616 A019621 A335263
KEYWORD
nonn,base
STATUS
approved