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%I #13 Jan 27 2022 22:44:25
%S 2,5,5,5,5,2,5,5,2,2,2,2,5,5,2,2,2,2,2,5,5,5,5,2,5,5,5,2,2,5,5,5,5,5,
%T 5,5,5,5,5,2,5,5,2,5,2,5,2,2,5,2,2,2,2,5,5,5,5,5,2,2,5,5,2,5,2,5,5,5,
%U 2,5,2,2,2,5,2,2,2,5,5,2,2,2,5,2,5,2,5,5,2,2,5,5,2,5,2,2,5,2,2,2,2,5,2,5,5,2,5,2
%N If any power of 2 ends with k 2's and 5's, they must be the first k terms of this sequence in reverse order.
%H Ray Chandler, <a href="/A023398/b023398.txt">Table of n, a(n) for n = 1..10000</a>
%K nonn,base
%O 1,1
%A _David W. Wilson_
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