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%I #14 Mar 29 2020 17:11:56
%S 0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0,
%T 1,0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,
%U 0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,1,0
%N Number of 5^m between 2^n and 2^(n+1).
%C All terms <= 1; each 1 is followed by either one or two 0's. - _Robert Israel_, Mar 29 2020
%H Robert Israel, <a href="/A022925/b022925.txt">Table of n, a(n) for n = 0..10000</a>
%F a(n) = floor((n+1)*log_5(2))-floor(n*log_5(2)) - Stephen P. Glasby (GlasbyS(AT)cwu.edu), Jul 29 2003
%p F:= [seq(floor(n*log[5](2)),n=0..101)]:
%p F[2..-1]-F[1..-2]; # _Robert Israel_, Mar 29 2020
%o (PARI) logint(2^(n+1),5)-logint(2^n,5) \\ _Charles R Greathouse IV_, Jan 16 2017
%K nonn
%O 0,1
%A _Clark Kimberling_
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