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a(n) = n*(29*n - 1)/2.
2

%I #21 Aug 24 2017 16:34:50

%S 0,14,57,129,230,360,519,707,924,1170,1445,1749,2082,2444,2835,3255,

%T 3704,4182,4689,5225,5790,6384,7007,7659,8340,9050,9789,10557,11354,

%U 12180,13035,13919,14832,15774,16745

%N a(n) = n*(29*n - 1)/2.

%H G. C. Greubel, <a href="/A022286/b022286.txt">Table of n, a(n) for n = 0..5000</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1).

%F a(n) = 29*n + a(n-1) - 15 for n>0, a(0)=0. - _Vincenzo Librandi_, Aug 04 2010

%F G.f.: x*(14 + 15*x)/(1 - x)^3. - _R. J. Mathar_, Aug 04 2016

%F a(n) = A000217(15*n-1) - A000217(14*n-1). - _Bruno Berselli_, Oct 14 2016

%F E.g.f.: (x/2)*(29*x + 28)*exp(x). - _G. C. Greubel_, Aug 24 2017

%t Table[n (29 n - 1)/2, {n, 0, 40}] (* _Bruno Berselli_, Oct 14 2016 *)

%o (PARI) a(n)=n*(29*n-1)/2 \\ _Charles R Greathouse IV_, Jun 17 2017

%Y Cf. A000217, A022287.

%Y Cf. similar sequences listed in A022288.

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_