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Expansion of 1/((1-x)(1-2x)(1-3x)(1-11x)).
1

%I #14 Sep 08 2022 08:44:45

%S 1,17,212,2422,26943,297339,3273754,36020624,396255365,4358895541,

%T 47948112576,527430027306,5801732675467,63819066571823,

%U 702009753747878,7722107355665668,84943181105770449,934374992744081385

%N Expansion of 1/((1-x)(1-2x)(1-3x)(1-11x)).

%H Vincenzo Librandi, <a href="/A021054/b021054.txt">Table of n, a(n) for n = 0..200</a>

%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (17,-77,127,-66).

%F a(0)=1, a(1)=17; for n>1, a(n) = 14*a(n-1) -33*a(n-2) +2^n - 1. - _Vincenzo Librandi_, Jul 05 2013

%F a(0)=1, a(1)=17, a(2)=212, a(3)=2422; for n>3, a(n) = 17*a(n-1) -77*a(n-2) +127*a(n-3) -66*a(n-4). - _Vincenzo Librandi_, Jul 05 2013

%F a(n) = (11^(n+3) -45*3^(n+3) + 80*2^(n+3) - 36)/720. [_Yahia Kahloune_, Jul 07 2013]

%t CoefficientList[Series[1 / ((1 - x) (1 - 2 x) (1 - 3 x) (1 - 11 x)), {x, 0, 20}], x] (* _Vincenzo Librandi_, Jul 05 2013 *)

%o (Magma) m:=25; R<x>:=PowerSeriesRing(Integers(), m); Coefficients(R!(1/((1-x)*(1-2*x)*(1-3*x)*(1-11*x)))); /* or */ I:=[1, 17, 212, 2422]; [n le 4 select I[n] else 17*Self(n-1)-77*Self(n-2)+127*Self(n-3)-66*Self(n-4): n in [1..25]]; // _Vincenzo Librandi_, Jul 05 2013

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_.