OFFSET
1,1
COMMENTS
It is extremely probable that a(n) = 2 for all n >= 169.
LINKS
Seiichi Manyama, Table of n, a(n) for n = 1..10000
PROG
(Python)
def a(n):
if n == 1: return 1023456789
an = 2
while not(len(set(str(an**n))) == 10): an += 1
return an
print([a(n) for n in range(1, 90)]) # Michael S. Branicky, Jul 04 2021
CROSSREFS
KEYWORD
nonn,base
AUTHOR
STATUS
approved