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A019514
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a(n) = (n!)^3 + 1.
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3
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2, 2, 9, 217, 13825, 1728001, 373248001, 128024064001, 65548320768001, 47784725839872001, 47784725839872000001, 63601470092869632000001, 109903340320478724096000001, 241457638684091756838912000001
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OFFSET
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0,1
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COMMENTS
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Since this is a sum of two cubes, it can be factorized. So all terms are divisible by n!+1. Thus only two primes occur in this sequence: a(0) and a(1). - Dmitry Kamenetsky, Sep 30 2008
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REFERENCES
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M. Le, On the Interesting Smarandache Product Sequences, Smarandache Notions Journal, Vol. 9, No. 1-2, 1998, 133-134.
M. Le, The Primes in Smarandache Power Product Sequences, Smarandache Notions Journal, Vol. 9, No. 1-2, 1998, 96-97.
F. Iacobescu, Smarandache Partition Type and Other Sequences, Bull. Pure Appl. Sciences, Vol. 16E, No. 2 (1997), pp. 237-240.
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LINKS
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Eric Weisstein's World of Mathematics, Factorial
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MATHEMATICA
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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R. Muller
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STATUS
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approved
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