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%I #16 Nov 06 2017 16:54:25
%S 1,2,3,6,11,22,33,66
%N Divisors of 66.
%C There are only three ways to partition 66 into its distinct divisors (see A033630), specifically: 33 + 22 + 6 + 3 + 2 = 33 + 22 + 11 = 66. - _Alonso del Arte_, Nov 06 2017
%H <a href="/index/Di#divisors">Index entries for sequences related to divisors of numbers</a>
%t Divisors[66] (* _Alonso del Arte_, Nov 06 2017 *)
%o (PARI) divisors(66) \\ _Charles R Greathouse IV_, Jun 22 2017
%K nonn,fini,full,easy
%O 1,2
%A _N. J. A. Sloane_.