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Powers of sqrt(22) rounded down.
1

%I #17 Sep 08 2022 08:44:43

%S 1,4,22,103,484,2270,10648,49943,234256,1098758,5153632,24172676,

%T 113379904,531798888,2494357888,11699575548,54875873536,257390662067,

%U 1207269217792,5662594565481,26559922791424

%N Powers of sqrt(22) rounded down.

%H Vincenzo Librandi, <a href="/A017970/b017970.txt">Table of n, a(n) for n = 0..700</a>

%F a(n) = floor(sqrt(22^n)). - _Vincenzo Librandi_, Jun 24 2011

%t Floor[(Sqrt[22])^Range[0,30]] (* _Harvey P. Dale_, Jul 16 2020 *)

%o (Magma) [Floor(Sqrt(22^n)): n in [0..30]]; // _Vincenzo Librandi_, Jun 24 2011

%o (PARI) a(n)=sqrtint(22^n) \\ _Charles R Greathouse IV_, Nov 18 2011

%Y Cf. A010478 (sqrt(22)).

%K nonn

%O 0,2

%A _N. J. A. Sloane_