%I #30 Jun 19 2024 10:36:18
%S 1,3,5,12,25,56,125,280,625,1398,3125,6988,15625,34939,78125,174693,
%T 390625,873465,1953125,4367321,9765625,21836602,48828125,109183007,
%U 244140625,545915034,1220703125,2729575168
%N Powers of sqrt(5) rounded up.
%H Vincenzo Librandi, <a href="/A017921/b017921.txt">Table of n, a(n) for n = 0..1000</a>
%e sqrt(5)^3 = 11.18033988749895... so a(3) = 12.
%e sqrt(5)^4 = 25, so a(4) = 25.
%e sqrt(5)^5 = 55.90169943749474241... so a(5) = 56.
%t Ceiling[Sqrt[5]^Range[0, 40]] (* _Vincenzo Librandi_, Nov 20 2011 *)
%o (Magma) [Ceiling(Sqrt(5^n)): n in [0..40]]; // _Vincenzo Librandi_, Nov 20 2011
%o (PARI) a(n) = ceil(sqrt(5^n)); \\ _Michel Marcus_, Dec 14 2017
%o (Python)
%o from math import isqrt
%o def A017921(n): return isqrt(5**n)+(n&1) # _Chai Wah Wu_, Jun 19 2024
%Y Cf. A017919, A017920.
%K nonn,easy
%O 0,2
%A _N. J. A. Sloane_