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a(n) = (12n+11)^7.
1

%I #26 Oct 29 2022 09:33:56

%S 19487171,3404825447,64339296875,506623120463,2488651484819,

%T 9095120158391,27136050989627,69833729609375,160578147647843,

%U 337931541778439,662062621900811,1222791080775407,2149422977421875

%N a(n) = (12n+11)^7.

%H Vincenzo Librandi, <a href="/A017659/b017659.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (8,-28,56,-70,56,-28,8,-1).

%F a(n) = 8*a(n-1)-28*a(n-2)+56*a(n-3)- 70*a(n-4)+ 56*a(n-5)- 28*a(n-6)+ 8*a(n-7)-a(n-8). - _Harvey P. Dale_, May 16 2012

%F a(n) = A001015(A017653(n)). - _Michel Marcus_, Oct 29 2022

%t (12Range[0,20]+11)^7 (* _Harvey P. Dale_, May 16 2012 *)

%t LinearRecurrence[{8,-28,56,-70,56,-28,8,-1},{19487171,3404825447,64339296875,506623120463,2488651484819,9095120158391,27136050989627,69833729609375},20] (* _Harvey P. Dale_, May 16 2012 *)

%o (Magma) [(12*n+11)^7: n in [0..15]]; // _Vincenzo Librandi_, May 21 2012

%Y Cf. A001015, A017653.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_.