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a(n) = (12*n + 7)^3.
1

%I #15 Dec 24 2025 17:09:59

%S 343,6859,29791,79507,166375,300763,493039,753571,1092727,1520875,

%T 2048383,2685619,3442951,4330747,5359375,6539203,7880599,9393931,

%U 11089567,12977875,15069223,17373979,19902511,22665187,25672375,28934443,32461759,36264691,40353607,44738875,49430863

%N a(n) = (12*n + 7)^3.

%H Matthew House, <a href="/A017607/b017607.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).

%F G.f.: (343+5487*x+4413*x^2+125*x^3)/(1-x)^4.

%F a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4). - _Wesley Ivan Hurt_, Sep 05 2025

%t (12 Range[0, 40] + 7)^3 (* _Wesley Ivan Hurt_, Sep 05 2025 *)

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_