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a(n) = (10*n+8)^2.
1

%I #13 Sep 08 2022 08:44:42

%S 64,324,784,1444,2304,3364,4624,6084,7744,9604,11664,13924,16384,

%T 19044,21904,24964,28224,31684,35344,39204,43264,47524,51984,56644,

%U 61504,66564,71824,77284,82944,88804

%N a(n) = (10*n+8)^2.

%H Vincenzo Librandi, <a href="/A017366/b017366.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1).

%F a(n) = 4*A016898(n). - _Michel Marcus_, Aug 26 2015

%t (10 Range[0,30]+8)^2 (* or *) LinearRecurrence[{3,-3,1},{64,324,784},30] (* _Harvey P. Dale_, Dec 17 2016 *)

%o (Magma) [(10*n+8)^2: n in [0..40]]; // _Vincenzo Librandi_, Aug 31 2011

%o (PARI) a(n) = (10*n+8)^2; \\ _Michel Marcus_, Aug 26 2015

%Y Cf. A016898.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_.