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a(n) = (10*n + 4)^9.
1

%I #16 Sep 08 2022 08:44:42

%S 262144,20661046784,2641807540224,60716992766464,618121839509504,

%T 3904305912313344,18014398509481984,66540410775079424,

%U 208215748530929664,572994802228616704,1423311812421484544,3251948521156637184

%N a(n) = (10*n + 4)^9.

%H Vincenzo Librandi, <a href="/A017325/b017325.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (10, -45, 120, -210, 252, -210, 120, -45, 10, -1).

%t (10*Range[0,20]+4)^9 (* or *) LinearRecurrence[{10,-45,120,-210,252,-210,120,-45,10,-1},{262144,20661046784,2641807540224,60716992766464,618121839509504,3904305912313344,18014398509481984,66540410775079424,208215748530929664,572994802228616704},20] (* _Harvey P. Dale_, Jul 13 2016 *)

%o (Magma) [(10*n+4)^9: n in [0..20] ]; // _Vincenzo Librandi_, Aug 01 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_