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a(n) = (10*n + 4)^3.
2

%I #17 Sep 08 2022 08:44:42

%S 64,2744,13824,39304,85184,157464,262144,405224,592704,830584,1124864,

%T 1481544,1906624,2406104,2985984,3652264,4410944,5268024,6229504,

%U 7301384,8489664,9800344,11239424

%N a(n) = (10*n + 4)^3.

%H Vincenzo Librandi, <a href="/A017319/b017319.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4, -6, 4, -1).

%F a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4); a(0)=64, a(1)=2744, a(2)=13824, a(3)=39304. - _Harvey P. Dale_, Oct 01 2014

%F G.f.: 8*(8 + 311*x + 404*x^2 + 27*x^3)/(x-1)^4. - _R. J. Mathar_, Mar 20 2018

%t (10*Range[0,30]+4)^3 (* or *) LinearRecurrence[{4,-6,4,-1},{64,2744,13824,39304},30] (* _Harvey P. Dale_, Oct 01 2014 *)

%o (Magma) [(10*n+4)^3: n in [0..40] ]; // _Vincenzo Librandi_, Aug 01 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_