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a(n) = (10*n + 1)^9.
2

%I #12 Sep 08 2022 08:44:42

%S 1,2357947691,794280046581,26439622160671,327381934393961,

%T 2334165173090451,11694146092834141,45848500718449031,

%U 150094635296999121,427929800129788411,1093685272684360901,2558036924386500591

%N a(n) = (10*n + 1)^9.

%H Vincenzo Librandi, <a href="/A017289/b017289.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (10, -45, 120, -210, 252, -210, 120, -45, 10, -1).

%o (Magma) [(10*n+1)^9: n in [0..20]]; // _Vincenzo Librandi_, Jul 30 2011

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_