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a(n) = (9*n + 5)^12.
1

%I #14 Sep 08 2022 08:44:42

%S 244140625,56693912375296,21914624432020321,1152921504606846976,

%T 22563490300366186081,244140625000000000000,1779197418239532716881,

%U 9774779120406941925376,43439888521963583647921,163674647745587512938496

%N a(n) = (9*n + 5)^12.

%H Vincenzo Librandi, <a href="/A017232/b017232.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13, -78, 286, -715, 1287, -1716, 1716, -1287, 715, -286, 78, -13, 1).

%t (9*Range[0,20]+5)^12 (* _Harvey P. Dale_, Nov 08 2013 *)

%o (Magma) [(9*n+5)^12: n in [0..10]]; // _Vincenzo Librandi_, Jul 24 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_