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a(n) = (9*n + 4)^12.
1

%I #15 Sep 08 2022 08:44:42

%S 16777216,23298085122481,12855002631049216,787662783788549761,

%T 16777216000000000000,191581231380566414401,1449225352009601191936,

%U 8182718904632857144561,37133262473195501387776,142241757136172119140625

%N a(n) = (9*n + 4)^12.

%H Vincenzo Librandi, <a href="/A017220/b017220.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13, -78, 286, -715, 1287, -1716, 1716, -1287, 715, -286, 78, -13, 1).

%o (Magma) [(9*n+4)^12: n in [0..15]]; // _Vincenzo Librandi_, Jul 24 2011

%Y Cf. A008456 (n^12), A017209 (9*n+4).

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_