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a(n) = (9*n + 4)^5.
1

%I #14 Sep 04 2024 23:23:35

%S 1024,371293,5153632,28629151,102400000,282475249,656356768,

%T 1350125107,2535525376,4437053125,7339040224,11592740743,17623416832,

%U 25937424601,37129300000,51888844699,71008211968

%N a(n) = (9*n + 4)^5.

%H Vincenzo Librandi, <a href="/A017213/b017213.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (6,-15,20,-15,6,-1).

%F G.f.: ( 1024 + 365149*x + 2941234*x^2 + 3256274*x^3 + 519074*x^4 + 3125*x^5 ) / (x-1)^6. - _R. J. Mathar_, Jul 14 2016

%t (9*Range[0,20]+4)^5 (* or *) LinearRecurrence[{6,-15,20,-15,6,-1},{1024,371293,5153632,28629151,102400000,282475249},20] (* _Harvey P. Dale_, Sep 04 2024 *)

%o (Magma) [(9*n+4)^5: n in [0..25]]; // _Vincenzo Librandi_, Jul 24 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_