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a(n) = (9*n + 4)^3.
1

%I #24 May 26 2024 01:16:41

%S 64,2197,10648,29791,64000,117649,195112,300763,438976,614125,830584,

%T 1092727,1404928,1771561,2197000,2685619,3241792,3869893,4574296,

%U 5359375,6229504,7189057,8242408

%N a(n) = (9*n + 4)^3.

%H Vincenzo Librandi, <a href="/A017211/b017211.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).

%F a(n) = A017209(n)^3 = A000578(A017209(n)). - _Wesley Ivan Hurt_, Jan 22 2014

%F G.f.: (64+1941*x+2244*x^2+125*x^3)/(x-1)^4. - _R. J. Mathar_, Jul 14 2016

%F a(n) = 4*a(n-1)-6*a(n-2)+4*a(n-3)-a(n-4). - _Wesley Ivan Hurt_, May 26 2024

%p A017211:=n->(9*n+4)^3; seq(A017211(n), n=0..35); # _Wesley Ivan Hurt_, Jan 22 2014

%t Table[(9n+4)^3, {n, 0, 35}] (* _Wesley Ivan Hurt_, Jan 22 2014 *)

%t LinearRecurrence[{4,-6,4,-1},{64,2197,10648,29791},30] (* _Harvey P. Dale_, Jan 21 2017 *)

%o (Magma) [(9*n+4)^3: n in [0..35]]; // _Vincenzo Librandi_, Jul 25 2011

%Y Cf. A000578 (n^3), A017209 (9*n+4).

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_