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a(n) = (9*n + 3)^8.
1

%I #12 Sep 08 2022 08:44:42

%S 6561,429981696,37822859361,656100000000,5352009260481,28179280429056,

%T 111429157112001,360040606269696,1001129150390625,2478758911082496,

%U 5595818096650401,11716593810022656,23045377697175681

%N a(n) = (9*n + 3)^8.

%H Vincenzo Librandi, <a href="/A017204/b017204.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_09">Index entries for linear recurrences with constant coefficients</a>, signature (9, -36, 84, -126, 126, -84, 36, -9, 1).

%o (Magma) [(9*n+3)^8: n in [0..20]]; // _Vincenzo Librandi_, Jul 23 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_