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a(n) = (9*n + 2)^12.
1

%I #14 Oct 15 2023 19:19:32

%S 4096,3138428376721,4096000000000000,353814783205469041,

%T 9065737908494995456,116191483108948578241,951166013805414055936,

%U 5688009063105712890625,26963771415920784510976,106890007738661124410161

%N a(n) = (9*n + 2)^12.

%H Vincenzo Librandi, <a href="/A017196/b017196.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13, -78, 286, -715, 1287, -1716, 1716, -1287, 715, -286, 78, -13, 1).

%t (9*Range[0,20]+2)^12 (* or *) LinearRecurrence[{13,-78,286,-715,1287,-1716,1716,-1287,715,-286,78,-13,1},{4096,3138428376721,4096000000000000,353814783205469041,9065737908494995456,116191483108948578241,951166013805414055936,5688009063105712890625,26963771415920784510976,106890007738661124410161,367666387654882241806336,1126825030131969720661201,3138428376721000000000000},20] (* _Harvey P. Dale_, Oct 15 2023 *)

%o (Magma) [(9*n+2)^12: n in [0..10]]; // _Vincenzo Librandi_, Jul 23 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_