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a(n) = (9*n + 1)^3.
1

%I #15 Jan 01 2024 19:45:15

%S 1,1000,6859,21952,50653,97336,166375,262144,389017,551368,753571,

%T 1000000,1295029,1643032,2048383,2515456,3048625,3652264,4330747,

%U 5088448,5929741,6859000,7880599,8998912

%N a(n) = (9*n + 1)^3.

%H Vincenzo Librandi, <a href="/A017175/b017175.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).

%F G.f.: ( 1 + 996*x + 2865*x^2 + 512*x^3 ) / (x-1)^4. - _R. J. Mathar_, Jul 14 2016

%t (9 Range[0, 30] + 1)^3 (* _Wesley Ivan Hurt_, Jan 01 2024 *)

%o (Magma) [(9*n+1)^3: n in [0..40]]; // _Vincenzo Librandi_, Aug 30 2011

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_