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a(n) = (8*n + 1)^4.
1

%I #18 Dec 05 2025 10:48:43

%S 1,6561,83521,390625,1185921,2825761,5764801,10556001,17850625,

%T 28398241,43046721,62742241,88529281,121550625,163047361,214358881,

%U 276922881,352275361,442050625,547981281,671898241,815730721,981506241,1171350625,1387488001,1632240801,1908029761,2217373921

%N a(n) = (8*n + 1)^4.

%H Vincenzo Librandi, <a href="/A017080/b017080.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_05">Index entries for linear recurrences with constant coefficients</a>, signature (5,-10,10,-5,1).

%F G.f.: -(1 + 6556*x + 50726*x^2 + 38620*x^3 + 2401*x^4)/(x-1)^5. - _R. J. Mathar_, Jul 14 2016

%t (8*Range[0, 30] + 1)^4 (* _Paolo Xausa_, Dec 05 2025 *)

%o (Magma) [(8*n+1)^4: n in [0..40]]; // _Vincenzo Librandi_, Jul 11 2011

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_