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a(n) = (6*n + 5)^10.
3

%I #19 Apr 01 2022 09:11:22

%S 9765625,25937424601,2015993900449,41426511213649,420707233300201,

%T 2758547353515625,13422659310152401,52599132235830049,

%U 174887470365513049,511116753300641401,1346274334462890625,3255243551009881201,7326680472586200649,15516041187205853449

%N a(n) = (6*n + 5)^10.

%H Vincenzo Librandi, <a href="/A016978/b016978.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (11,-55,165,-330,462,-462,330,-165,55,-11,1).

%F From _Amiram Eldar_, Apr 01 2022: (Start)

%F a(n) = A016969(n)^10 = A016970(n)^5 = A016973(n)^2.

%F Sum_{n>=0} 1/a(n) = PolyGamma(9, 5/6)/21941965946880. (End)

%t (6*Range[0,20]+5)^10 (* _Harvey P. Dale_, Aug 26 2012 *)

%o (Magma) [(6*n+5)^10: n in [0..30]]; // _Vincenzo Librandi_, May 14 2011

%Y Cf. A016969 (6*n + 5), A016970, A016971, A016972, A016973, A016974, A016975, A016976, A016977.

%Y Subsequence of A008454 (n^10).

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_