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a(n) = (6*n + 5)^8.
5

%I #17 Apr 01 2022 09:11:10

%S 390625,214358881,6975757441,78310985281,500246412961,2251875390625,

%T 7984925229121,23811286661761,62259690411361,146830437604321,

%U 318644812890625,645753531245761,1235736291547681,2252292232139041,3936588805702081,6634204312890625,10828567056280801

%N a(n) = (6*n + 5)^8.

%H Vincenzo Librandi, <a href="/A016976/b016976.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_09">Index entries for linear recurrences with constant coefficients</a>, signature (9,-36,84,-126,126,-84,36,-9,1).

%F From _Amiram Eldar_, Apr 01 2022: (Start)

%F a(n) = A016969(n)^8 = A016970(n)^4 = A016972(n)^2.

%F Sum_{n>=0} 1/a(n) = PolyGamma(7, 5/6)/8465264640. (End)

%t Table[(6*n + 5)^8, {n, 0, 20}] (* _Amiram Eldar_, Apr 01 2022 *)

%o (Magma) [(6*n+5)^8: n in [0..20]]; // _Vincenzo Librandi_, May 12 2011

%Y Cf. A016969 (6*n + 5), A016970, A016971, A016972, A016973, A016974, A016975.

%Y Subsequence of A001016 (n^8).

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_