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a(n) = (4n+2)^10.
2

%I #13 Apr 21 2023 05:46:57

%S 1024,60466176,10000000000,289254654976,3570467226624,26559922791424,

%T 141167095653376,590490000000000,2064377754059776,6278211847988224,

%U 17080198121677824,42420747482776576,97656250000000000,210832519264920576,430804206899405824,839299365868340224

%N a(n) = (4n+2)^10.

%H T. D. Noe, <a href="/A016834/b016834.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (11,-55,165,-330,462,-462,330,-165,55,-11,1).

%F From _Amiram Eldar_, Apr 21 2023: (Start)

%F a(n) = A016825(n)^10.

%F a(n) = 2^10*A016762(n).

%F Sum_{n>=0} 1/a(n) = 31*Pi^10/2972712960. (End)

%t Table[(4*n+2)^10, {n, 0, 20}] (* _Amiram Eldar_, Apr 21 2023 *)

%Y Cf. A016762, A016825.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_