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a(n) = (4n+2)^7.
1

%I #11 Apr 21 2023 05:46:48

%S 128,279936,10000000,105413504,612220032,2494357888,8031810176,

%T 21870000000,52523350144,114415582592,230539333248,435817657216,

%U 781250000000,1338925209984,2207984167552,3521614606208,5455160701056,8235430000000,12151280273024,17565568854912,24928547056768

%N a(n) = (4n+2)^7.

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (8,-28,56,-70,56,-28,8,-1).

%F From _Amiram Eldar_, Apr 21 2023: (Start)

%F a(n) = A016825(n)^7.

%F a(n) = 2^7*A016759(n).

%F Sum_{n>=0} 1/a(n) = 127*zeta(7)/16384.

%F Sum_{n>=0} (-1)^n/a(n) = 61*Pi^7/23592960. (End)

%t Table[(4*n + 2)^7, {n, 0, 20}] (* _Amiram Eldar_, Apr 21 2023 *)

%Y Cf. A013665, A016759, A016825.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_