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a(n) = (4n)^10.
1

%I #12 Mar 08 2023 12:16:53

%S 0,1048576,1073741824,61917364224,1099511627776,10240000000000,

%T 63403380965376,296196766695424,1125899906842624,3656158440062976,

%U 10485760000000000,27197360938418176,64925062108545024,144555105949057024,303305489096114176,604661760000000000

%N a(n) = (4n)^10.

%H T. D. Noe, <a href="/A016810/b016810.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (11, -55, 165, -330, 462, -462, 330, -165, 55, -11, 1).

%F a(n) = 11*a(n-1) - 55*a(n-2) + 165*a(n-3) - 330*a(n-4) + 462*a(n-5) - 462*a(n-6) + 330*a(n-7) - 165*a(n-8) + 55*a(n-9) - 11*a(n-10) + a(n-11). - _Wesley Ivan Hurt_, Mar 08 2023

%t (4*Range[0,20])^10 (* _Harvey P. Dale_, Aug 03 2019 *)

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_.