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%I #25 Sep 08 2022 08:44:41
%S 1,177147,48828125,1977326743,31381059609,285311670611,1792160394037,
%T 8649755859375,34271896307633,116490258898219,350277500542221,
%U 952809757913927,2384185791015625,5559060566555523,12200509765705829,25408476896404831,50542106513726817,96549157373046875
%N a(n) = (2*n+1)^11.
%H Vincenzo Librandi, <a href="/A016763/b016763.txt">Table of n, a(n) for n = 0..10000</a>
%H <a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (12,-66,220,-495,792,-924,792,-495,220,-66,12,-1).
%F G.f.: (1+x)*(x^10 +177134*x^9 +46525293*x^8 +1356555432*x^7 +9480267666*x^6 +19107752148*x^5 +9480267666*x^4 +1356555432*x^3 +46525293*x^2+ 177134*x +1)/(x-1)^12 . - _R. J. Mathar_, Jul 07 2017
%F From _Amiram Eldar_, Oct 11 2020: (Start)
%F Sum_{n>=0} 1/a(n) = 2047*zeta(11)/2048.
%F Sum_{n>=0} (-1)^n/a(n) = 50521*Pi^11/14863564800. (End)
%t Table[(2*n+1)^11, {n,0,20}] (* _G. C. Greubel_, Sep 15 2018 *)
%t LinearRecurrence[{12,-66,220,-495,792,-924,792,-495,220,-66,12,-1},{1,177147,48828125,1977326743,31381059609,285311670611,1792160394037,8649755859375,34271896307633,116490258898219,350277500542221,952809757913927},20] (* _Harvey P. Dale_, Nov 15 2020 *)
%o (Magma) [(2*n+1)^11: n in [0..20]]; // _Vincenzo Librandi_, Sep 07 2011
%o (Maxima) A016763(n):=(2*n+1)^11$
%o makelist(A016763(n),n,0,20); /* _Martin Ettl_, Nov 12 2012 */
%o (PARI) vector(20, n, n--; (2*n+1)^11) \\ _G. C. Greubel_, Sep 15 2018
%Y Cf. A016751.
%K nonn,easy
%O 0,2
%A _N. J. A. Sloane_
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