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Expansion of 1/((1-3x)(1-11x)).
1

%I #20 Dec 18 2018 13:16:02

%S 1,14,163,1820,20101,221354,2435623,26794040,294741001,3242170694,

%T 35663936683,392303480660,4315338818701,47468728600034,

%U 522156019383343,5743716227565680,63180878546269201,694989664138101374

%N Expansion of 1/((1-3x)(1-11x)).

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (14,-33)

%F a(n) = 14*a(n-1) - 33*a(n-2), n >= 2. - _Vincenzo Librandi_, Mar 14 2011

%F a(n) = (-3^(n+1) + 11^(n+1))/8. - _R. J. Mathar_, Mar 15 2011

%t Join[{a=1,b=14},Table[c=14*b-33*a;a=b;b=c,{n,60}]] (* _Vladimir Joseph Stephan Orlovsky_, Feb 01 2011 *)

%t CoefficientList[Series[1/((1-3x)(1-11x)),{x,0,30}],x] (* or *) LinearRecurrence[ {14,-33},{1,14},30] (* _Harvey P. Dale_, Dec 18 2018 *)

%K nonn

%O 0,2

%A _N. J. A. Sloane_