%I #15 Jan 08 2018 02:48:52
%S 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
%T 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
%U 0,0,0,0,0,0,0,0,0,0,0,0,0
%N Inverse of 1513th cyclotomic polynomial.
%C Periodic with period length 1513. - _Ray Chandler_, Apr 07 2017
%H Ray Chandler, <a href="/A015522/b015522.txt">Table of n, a(n) for n = 0..2000</a>
%H <a href="/index/Rec#order_1408">Index entries for linear recurrences with constant coefficients</a>, order 1408.
%H <a href="/index/Pol#poly_cyclo_inv">Index to sequences related to inverse of cyclotomic polynomials</a>
%p with(numtheory,cyclotomic); c := n->series(1/cyclotomic(n,x),x,80);
%t CoefficientList[Series[1/Cyclotomic[1513, x], {x, 0, 100}], x] (* _G. C. Greubel_, Jan 07 2018 *)
%o (PARI) Vec(1/polcyclo(1513) + O(x^100)) \\ _G. C. Greubel_, Jan 07 2018
%K sign
%O 0,1
%A _Simon Plouffe_